2SD11490RL [Panasonic]

2SD11490RL Overview

In this device, the DC current gain is 400 @ 2mA 10V, which is the ratio between the base current and the collector current.Single BJT transistor means that Ic is at Single BJT transistors maximum value (saturated), so the vce saturation(Max) is equal to 200mV @ 1mA, 10mA.As defined by current rating, the maximum current a fuse can carry without deteriorating too much is 20mA for this device.Input voltage breakdown is available at 100V volts.Product comes in the supplier's device package Mini3-G1.There is a 100V maximal voltage in the device due to collector-emitter breakdown.Single BJT transistor is possible for the collector current to fall as low as 20mA volts at Single BJT transistors maximum.

2SD11490RL Features

the DC current gain for this device is 400 @ 2mA 10V
the vce saturation(Max) is 200mV @ 1mA, 10mA
the current rating of this device is 20mA
the supplier device package of Mini3-G1

2SD11490RL Applications

There are a lot of Panasonic Electronic Components
2SD11490RL applications of single BJT transistors.

• Inverter
• Interface
• Driver
• Muting