2SA06840R [Panasonic]

2SA06840R Overview

In this device, the DC current gain is 120 @ 500mA 10V, which is the ratio between the base current and the collector current.Single BJT transistor means that Ic is at Single BJT transistors maximum value (saturated), so the vce saturation(Max) is equal to 400mV @ 50mA, 500mA.As defined by current rating, the maximum current a fuse can carry without deteriorating too much is -1A for this device.Input voltage breakdown is available at 50V volts.Product comes in the supplier's device package TO-92L-A1.There is a 50V maximal voltage in the device due to collector-emitter breakdown.Single BJT transistor is possible for the collector current to fall as low as 1A volts at Single BJT transistors maximum.

2SA06840R Features

the DC current gain for this device is 120 @ 500mA 10V
the vce saturation(Max) is 400mV @ 50mA, 500mA
the current rating of this device is -1A
the supplier device package of TO-92L-A1

2SA06840R Applications

There are a lot of Panasonic Electronic Components
2SA06840R applications of single BJT transistors.

• Inverter
• Interface
• Driver
• Muting